5x^2-2x+41=0

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Solution for 5x^2-2x+41=0 equation:


Simplifying
5x2 + -2x + 41 = 0

Reorder the terms:
41 + -2x + 5x2 = 0

Solving
41 + -2x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
8.2 + -0.4x + x2 = 0

Move the constant term to the right:

Add '-8.2' to each side of the equation.
8.2 + -0.4x + -8.2 + x2 = 0 + -8.2

Reorder the terms:
8.2 + -8.2 + -0.4x + x2 = 0 + -8.2

Combine like terms: 8.2 + -8.2 = 0.0
0.0 + -0.4x + x2 = 0 + -8.2
-0.4x + x2 = 0 + -8.2

Combine like terms: 0 + -8.2 = -8.2
-0.4x + x2 = -8.2

The x term is -0.4x.  Take half its coefficient (-0.2).
Square it (0.04) and add it to both sides.

Add '0.04' to each side of the equation.
-0.4x + 0.04 + x2 = -8.2 + 0.04

Reorder the terms:
0.04 + -0.4x + x2 = -8.2 + 0.04

Combine like terms: -8.2 + 0.04 = -8.16
0.04 + -0.4x + x2 = -8.16

Factor a perfect square on the left side:
(x + -0.2)(x + -0.2) = -8.16

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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